2p^2+18p+36=0

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Solution for 2p^2+18p+36=0 equation: 



2p^2+18p+36=0

a = 2; b = 18; c = +36;
Δ = b2-4ac
Δ = 182-4·2·36
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*2}=\frac{-24}{4}
=-6
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*2}=\frac{-12}{4}
=-3
$

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